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I would start with the Ac method just for the reason that 6 isn''t a perfect square number.

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If i were to factor the equation, i would first start to see if the first and last terms are perfect squares. If they aren't perfect squares then the equation would be a trinomial.

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I would use the A times C method. I would multiply 6 and 2 to start. I would start that way because the coefficient of x^2 is greater than one.

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I would check if 6 and 2 (a&b) are perfect squares. Then I would do the AC method because 6 and 2 isn't a perfect square. Because of this I would multiply 6 and 2.

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I would use ac method, i would multiply 6 and -2 and it would give me -12. know I have to find the what multiplication gives me -12 and adds up to 7.

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Ac method

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Ac method will do

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To factor this equation, I would start off by seeing if the first term and last term are perfect squares. Because they're not and the equation is a trinomial, I would factor this equations using the AC method. To do this I would multiply the first and last term. This would have given me 12. Then I would find factors for 12 and replace the middle terms with the factors.

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if I were to factor that equation, first I would see if 6 and 2 are perfect squares, I find it to be the easiest that way. 2 is a perfect square, but 6 is not. Therefore, I woud have to use ac method.
I see that a = 6 and c = 2
I would then multiply 6 and 2 which gives me 12.
now I need to find factors that multiply to 12, but add to 7, which is the middle term/

3 times 4 gives me 12
3 plus 4 gives me 7

I bring the 6x^2 and put it my the parenthesis

(6x^2 + 3x) (7x + 2)

now I need to factor each parenthesis

6 and 3 both share a common factor, which is 3.

3x (2x +

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I will use the AC method because both 2 and 6 are not perfect squares
First I will multiply 6*2=12 then

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check if the numbers are perfect square and 2 and 6 are not so we'd do the Ac method.

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I would start by looking at what type of equation it is first since the 6 is greater than 1 I would do the AC method so I multiply 6 with 2 which would be 12 now I have to find what multiplies to 12 and adds to 7 which would be 4 and 3 so then I group them and write the final answer as ( x+4) (x+3)

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I would start with the AC method.Because 6 and 2 aren't perfect squares .But i know 6 and 2 have a common number is 2 but since thats out from their so from their i would use AC method.

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IF I TOLD YOU TO FACTOR THE FOLLOWING EXPRESSION. HOW WOULD YOU DO IT. IN WORDS. USE PROPER VOCABULARY. Where would you start? what method? why start that way? Why finish that way? etc. 

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IF I TOLD YOU TO FACTOR THE FOLLOWING EXPRESSION. HOW WOULD YOU DO IT. IN WORDS. USE PROPER VOCABULARY. Where would you start? what method? why start that way? Why finish that way? etc. 

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6x ² + 7x + 2