# data[].attributes.body
Q1
A. True
B. True

Q2
81/9 = 9
1 Book- 1 upon 9
1/9 x 40
40/9 Kg
40 / 9 = 4.4
40 Books = 4.4 Kg

Q3
255mm/3= 8.5
1 Day= 8.5cm
8.5 x 7 = 595

Therefore, 7 Days will have 595mm which is 59.5cm Rainfall at the same rate

Q4
2000L

Q5
TV
Protractor
A4 Blank Paper
Ruler

Q6
1. 1
2. 3
3. 8

# data[].attributes.body
595 mm rain

# data[].attributes.body
Q1
a) true
b) true
Q2=
81 books= 9kg
81/9 or 1/9 kg = 1 book
1/9 x 40=
9/40 =  4  4/9
Q3
255 mm in 3 days
255/3 = 85
85 mm = 1 day
85 x 7  = 595
1cm = 100 mm
595/100 = 5.95
Ans= 5.95 cm

# data[].attributes.body
Q1
(a)
16:24 =? 20:30
Simplest form of 16:24
=2:3

Simplest form of 20:30
=2:3

2:3 = 2:3 or 16:24 = 20:30
statement is true

(b)
32:64 =? 6:12
Simplest form of 32:64
=1:2

Simplest form of 6:12
=1:2

1:2=1:2 or 32:64= 6:12
Stament is true

Q2
81 book= 9 kg
1 book   = 1/9kg
40 books = 1/9 x 40
40 books = 40/9
40 books = 4 4/9
40 books = 4 4/9 kg

Q3
255mm     = 3 days of rainfall
255mm/3 = 1 day of rainfall
85 mm      = 1 day of rainfall
85 mmx7  = 7 day(1 week) of rainfall
595           = 7 day(1 week) of rainfall

1 cm       = 10mm
1 mm      = 1/10th(0.1) of a cm
595 mm = 59.5 cm

Therefore, there will be 59.5 cm of rain in 7 days or 1 week.
Q4
120l : 108km
120 and 108 hcf - 12
120/12 : 108/12
=10:9

𝓍 : 1800
10*𝓍 : 9*200
10*200 : 9*200
2000 :1 800

Therefore the truck will require
2000 liters for 180 kilometer

Q1
shape a - 1 line of symmetry
shape b - 3 lines of symmetry
shape c - 8 lines of symmetry

# data[].attributes.body
PROPORTION
Q1
a) True
b) True

Q2
Final- 4 4/9

Q3
Final- 59.5 cm rain in 7 days

Q4
2,000 liters

SYMMETRY
Q1
4 symmetrical objects:
-Chair
-Bottle
-Plate
-Yoga mat

Q2
a) 1
b) 3
c) 8

Q3
Drawn in NB

# data[].attributes.body
Q1 -
a - true
b - true

Q2-
81 ÷ 9 = 9
9 ÷ 9 = 1
1/9 = 1 book
1/9×40
= 4 4/9  kg

Thus , 40 books weigh 4 4/9  kg

Q3 -
3days = 255 mm rain
1 day = 255÷3
= 85 mm rain in 1 day
= 85× 7
=595 mm
=59.5
Thus , it will rain 59.5 cm in 7 days .

Q4 -
108:120::1800 : a
120 × 1800 = 216000
108 × 2000 = 216000
a = 2000
Thus , 1800 km will need 2000 litres

SYMMETRY
Q2 - 1 line
- 3 lines
- 8 lines

# data[].attributes.body
3.60kg  or  5kg

# data[].attributes.body
360kg

# data[].attributes.body
q1) a-True b-True
q2) 4.4kg
q3) 59.5cm of rain
q4) 2000 liters
q5) Window , Ball photo frame
q6) peacock-1 shape 1 -1 shape 2 -2

# data[].attributes.body
a)
16  : 24 :: 20 : 30
8 : 12       10 : 15
4 : 6         2  :  3
2 : 3  ::   20:30 simplify 2:3 too so true

b)
32 : 64 :: 6 : 12
16 : 32  :: 3 : 6
8 : 16
4 : 8
2 : 4

Q2 81 div 9 40 mult 360 but i think wrong ( IT IS WRONG)

Q3 255 mm so convert to cm 25.5 cm last 3 days so divide by 3 so 8.5 so then multiply by 7 it is 59.5 cm of rain

Q 4 120 litre of diseal and 108 so frasction that 120/108 then
simplify

the first one is 1 and the is 3 and the other is 4

# data[].attributes.body
q.1
1. 16:24::20:30
2:3 and 2:3
therefore 1 is true
2. 32: 64:: 6:12
1:2 and 1:2
therefore 2 is also true
q.2-
weight of 81 books= 9kg
weight of 40 books=  9/ 81= 1/9 x 40
= 4.4 kg
q.3-
rain in 3 days= 225 mm
rain in 1 week= 225mm/3 x7
85x 7
595 mm
59.5 mm

# data[].attributes.body
Q1
a. true
b.true

# data[].attributes.body
Q.1) a- True
16 x 30 = 480
24 x 20 = 480
480=480
b- True
12 x 32 = 384
64 x 6 = 384
384=384

Q.2) No. of Books= 81
Weight of books= 9 kg
1 book= 1/9 kg
=1/9 x 40
=1 x 40 = 40 / 9 = 4
So, 4  4/9 kg

Q.3) 255:3 :: X:7
=255 x 7 = 1785
=3 x X = 1785
X = 595
59.5 cm

Q.4) 120:108::x:1800
120 x 1800 = 216000
X x 108 = 216000
216000/108= 2000
2000 x 108= 216000
2000L
It will require 2000 L of Diesel.

# data[].attributes.body
Q1
A.true
Means and extreme method-
20x 24=480
30x 16=480
B.true
Means and extreme method-
12x 32=384
6x64=384
Q2
4 kg 4/9
Q3
255 /3=85
85mm= 1 day
85x7=595mm
1cm=10mm
595mm= 59.5cm
Q4
120:108::x:1800
120x1800=216000
216000/108=2000
2000L
Q5
Window
Bowl
Photo frame
Box
Q6
Peacock-1
Shape-3
Shape2-8

# data[].attributes.body
Q.1)A= True
=16x30=480
=24x20=480
=480=480
Therefore, 16: 24 :: 20 : 30

B= True
=32x12=384
=64x6=384
=384=384
Therefore, 32 : 64 :: 6 : 12

Q.2) 81 books=9 kg
so, 1 book= 81/9 kg=1 book= 1/9
1/9x40= 40/9
40÷9=4 remainder= 4
answer- 4 4/9 kg

Q.3) 3 days rain= 255mm
255÷3= 85
1 day rain= 85mm
85 x 7= 595
595÷10=59.5 cm

Therefore, in 7 days it will rain 59.5cm at the same rate

# data[].attributes.body
Q1.
a. True
b. True
Q3.
Amount of rain in 3 days= 255 mm
Amount of rain in 1 full week=?
= 255/3
= 85
1 day= 85 mm of rain
1 week= 7 days
= 85x 7
= 595 mm
Millimeter to Centimeter
= 595/10
=59.5 cm
Ans. 1 full week of rain will result in 59.5 cm of rain.
Q5.
1: Carrom Board
2: Laptop
3: Charging Adaptor
4: Sanitizer

# data[].attributes.body
A)TRUE
B)TRUE

# data[].attributes.body
Q1)
A.TRUE
B.TRUE

Q2)
7 days=595mm rain fall

# data[].attributes.body
a)true
b)True

# data[].attributes.body
Q1 )
a: True
b: true
Q2 )
Weight is 4.4 kg (original answer) for 40 books. (how did everyone get 360 kg???)
Q3)
59.5 cm of rain fell in 7 days.(8.5 per day)
lcm of 3 and 7 = 21
255 mm * 7 = 1785 mm
1785 mm / 21 = 85 mm
85 * 7 = 595 mm = 59.5 cm
Q4)
120 liters required for 108 km of distance
ratio is 9:10 simplified
so since the truck needs to go 1800 km
the truck needs 2000 liters

# data[].attributes.body
q1) a-True b -True
q2)