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Weak base Strong Acid

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Thank you Professor Gillings for all that you have taught us! Thank you for being caring,understanding and most importantly the best professor I've ever had since 1025! NOGGIN'

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Finding  (P.) S(H)erman 42 Wallaby Way, Sydney

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Finding  (P.) S(H)erman 42 Wallaby Way, Sydney

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WOOOO WE FOUND NEMO I MEAN THE pH!!

We're using the equation pH=-log[H^+] and plugging in 6.54*10^-6

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Now we use Ka*Kb=Kw and switch it around to Ka=Kw/Kb to then plug it into the equation from the ICE table from Bruce.

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(Fin)ding Ka by using Kb and The ICE TABLE!

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(Fin)ding Ka by using Kb and The ICE TABLE!

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Hold on tight Squirt!  This is the part we use raise pKb (4.19) to the 10^-4.19 and we get 6.46*10^-5 (that's Kb)

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Now that we have our initial concentration let's also create an equation using the ICE table in which what concentration will be present!

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I WHALEY NEED TO STOP WITH THESE PUNS BUT LET'S START (FIN)DING THE INITIAL CONCENTRATION 

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I WHALEY NEED TO STOP WITH THESE PUNS BUT LET'S START (FIN)DING THE INITIAL CONCENTRATION 

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Before we get into the ICEY FUN! we need to find out the initial concentration by dividing mols/total volume! (NOTE: DON'T FORGET TO ADD 0.160L+0.027L as the total volume

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HERE WE DON'T HAVE NEMO-SIS! Finding the moles of weak base from given! 

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HERE WE DON'T HAVE NEMO-SIS! Finding the moles of weak base from given! 

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Now that we have the # of moles of HNO3 given which is 0.4990 M which helps us solve for the volume of strong acid that we have to add (aka the amount of solution from the burette to get to the equivalence pt.)

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Remember to convert what you get! If this step isn't done...well REWIND

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To better understand the equation we create a chemical equation showing Trimeththylamine and Nitric Acid combining to form the equation below. Since it’s also a 1:1 ratio then the # of moles of weak base (CH3)3N will be the same number of moles of the strong acid HNO3.

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This question is asking us for the pH at the equivalence point. This is when the moles of the weak base will equal the moles of the strong acid.

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 BREAK DOWN THE PROBLEM AND SEE WHAT IS GIVEN.

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 BREAK DOWN THE PROBLEM AND SEE WHAT IS GIVEN.

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((CH3)3N):
- Volume: 160.0 mL
- Concentration: 0.6323 M
- pKb=4.19
HNO3:
- Concentration: 0.4990M

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YEP..IT'S A BOAT LOAD BUT WE GOT THIS..KEEP SWIMMING TO LEARN HOW TO SOLVE THIS SOLUTION TO RESCUE NEMO

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YEP..IT'S A BOAT LOAD BUT WE GOT THIS..KEEP SWIMMING TO LEARN HOW TO SOLVE THIS SOLUTION TO RESCUE NEMO

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I hope this presentation has you HOOKED on Titrations!

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I hope this presentation has you HOOKED on Titrations!

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The Chemistry Wiz titrates  160.0 mL of a 0.6323 M ((CH3)3N) solution with 0.4990 M HNO3 solution at 25 degrees Celsius.

Calculate the pH at equivalence. The pKb of ((CH3)3N) is 4.19.
Don't forget to round to 2 sig figs.

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LET’S GET READY TO SWIM THROUGH THIS PROBLEM & FIND NEMO!

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LET’S GET READY TO SWIM THROUGH THIS PROBLEM & FIND NEMO!

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Failing is not an option here.. Any fin is possible, don't trout yourself!