# data[].attributes.body
1.B = 3/12
2. picture
3. 1/12 + 1/12 + 1/12 = 3/12 or
12/12 - 8/12 - 1/12 = 3/12
total        A          left          B
over
4.We found out the total by  going down a layer from the top boxes.  We made a box just like it and and 12 boxes. The group A had taken everything but the left over and group b portion. so we had to subtract group A portion to the total, and then subtract the left over portion to the answer of the total minus group A's answer which equals group B's portion.

# data[].attributes.body
1.3/12

2.

3. 1/3 + 3/4= /12

4. rectangel then you do 3 lines

# data[].attributes.body
1.3/12
3.Group A (12/12 - 8/12=4/12) Group B (3/12)
4.I cut a rectangle into three pieces and cut it again vertically and made 12 pieces. In the picture it said group A had the most and group B had three pieces and next to it was left over. Then i counted three pieces that group B had and all together was twelve Pieces and got 3/12.

# data[].attributes.body
1.  3/12
2.
3. 1/12+1/12+1/12=3/12
4. We solved the problem by doing 1/12+1/12+1/12 three times and getting 3/12 .Group B had 3 pieces and group a had the rest but not the left over.

# data[].attributes.body
1. Group B took 3/12 of the casserole.
3. 1/3 x 3/4 = 3/12, and then 12/12 - 8/12 - 1/2 = 3/12.
4.we

# data[].attributes.body
1.What fraction did Group B take

2. insert picture

3. what is your number sentence ?

4. explain how you solved the problem