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y=(-6607/7500)x^2+(6607/2500)x+0

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Are solutions are (0,0) and (3,0). (0,0), which is also are y intercept, reprsent the hieght which the ball starts at. (3,0) represents the finally landing place of the ball a.k.a the bottom of the trash can.

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(1.5, 1.9821)
This represents the highest point at which the ball reaches

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Our Y-Intercept is 0. That represents the height at which the ball started.

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The easiest and quickest way to solve the equation is the quadratic formula.

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Our Video Representation of our Quadratic Problem!

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Quadratic Challenge Problem - Saxton, Amy, Brandon - 3rd Period

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1. List the points of the graph: (0,0) (1.5, 1.9821) (3,0). (Using Brandon as a reference point and measuring in feet, we then converted the max height, 6"9', to meters).

2. Square all of the x values, and place them within the first column of matrix A to find our a value (low to high going down). After, place the x values within the second column to find the value, and 1 for all the rows in the third column to find the c value.

3. Place all of the y values within matrix B, in the same order as matrix A.

4. Multiply the inverse of matrix A by matrix B.

5. Using the points within the matrix product, we now have our a, b, and c values, and can place them into the standard quadratic equation:
y=(-6607/7500)x^2+(6607/2500)x+0

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Saxton throws a paper ball from the ground in a squatting position. It leaves his hand and reaches a max height of 1.9812 meters. The bottom of the trash which he is aiming from is 3 meters away from him.

a. Draw a picture (or in our case show a video) and identify key points

b. Formulate and equation using either quadratic regression or matrices

c. Graph the situation

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The start to any great quadratic application problem is a fun, simple brain storm