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https://drive.google.com/open?id=0B_CQhOOIElrGdmZDTTJkOEJPMEE

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https://drive.google.com/open?id=0B07HyaGgcfW4c2s2bzlkcms2ZmM

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This article explains a lot about fibre, i think regarding the single mode part we can use in our report.
http://www.cisco.com/c/en/us/products/collateral/interfaces-modules/transceiver-modules/white_paper_c11-463661.html

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http://www.osa-opn.org/home/articles/volume_25/march_2014/features/sea_change_the_challenges_facing_submarine_optical/

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Length per cable = 25.2km
Number of cables = 6000 / 25.2 = 239 cables
Therefore, N = 238
Attenuation of cable, ⍺= 0.22dB / km
Loss of joint, Lj = 0.5dB
Back reflection of joint = -40dB
Loss of detector, Ld = -26dB
Power of system margin, Psm = 6dB (assume?)

Transceiver
Pout = 10.5dBm
Pin = -21.2dBm (min) AND -4.5dBm (max)

⍺Nl = Ps - Pr - N*Lj
N(⍺l +Lj) = Ps - Pr
N = (Ps - Pr) / (⍺l + Lj)

I could not find the minimum Pout detectable by the repeater, so I plan to install the connector when the power drops below the value detectable by the transceiver.

For first part, Ps = 10.5 dBm (From transceiver spec)
N = (10.5 - (-21.2)) / (0.22 * 25.2 + 0.5)
= 5.245   =  5    ∴ after first 5 connectors, we must install a repeater

After first repeater, Ps is the output of the repeater = 14 dBm (from repeater spec)
N = (14 - (-21.2)) / (0.22 * 25.2 + 0.5)
= 5.824   = 5    ∴ after 5 connectors, we must install another repeater

After the last repeater, there are 3 remaining connectors before reaching Tokyo. (238 % 5 = 3)
⍺Nl = Ps - Pr - N*Lj
Pr = Ps - N*Lj - ⍺Nl
= 14 - 3*0.5 - 0.22*3*25.2
= -4.132 dBm
This value is within the allowable range of the transceiver, lower than -4.5 dBm and higher than -21.2 dBm

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For wavelength 1310nm

https://www.finisar.com/sites/default/files/downloads/finisar_ftl4e1qe1c_40gbase-er4_40km_multirate_qsfp_optical_transceiver_preliminary_product_spec_reva4.pdf

This is the other transmitters I got from internet. This is more suitable for us

data rate : >40Gbps
distance up to 40km.

Hence, if we are using this transceiver, we can use it as both transmitter and receiver for our system. No multiplexers are required. Just we may need quite a few number of connectors as the max length is only 40km.

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For wavelength 1550nm.

I think this transmitter might suitable for us.
http://www.optocom.com/opt3285-5x.pdf

The optical transmitter with code  OPT3285-5E .

The specifications can be found in the link.

However, the problem we will be facing if using this transmitter is the data rate too low. Multiplexer may be needed.

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a. Minimum length of 6000 km
b. Data rate of 40 Gbps
c. Bit-error-rate < 10^-9

1. Minimum received power
2. Minimum transmitted power
3. Number of connectors
4. Type of fibre and optical amplifier

Refer Chap8

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Losses in Optical Fiber Communication System

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Losses in Optical Fiber Communication System

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As discussed in our lecture class today, There are 4 major losses in a optical fiber communication system:

- fiber loss
-connector loss
-power margin
-splice loss

I think we need to consider all these 4 losses in our system.

Also, joint loss (optional) depends on how our system is designed.

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ID: 1122700478
Username: shiningblast

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ID: 1122700478

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ID: 1122700807
Username: sinmin_22

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ID: 1122700325
Username: xinrong0815

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Please include a post with all your group members' real names, ID number and usernames.

Thanks

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Hello Everyone, this is our assignment discussion board :)

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Hello Everyone, this is our assignment discussion board :)