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Pt 2

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Part 2

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Q2. p2

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d=6
a1=6

an= a+(n-1)d
a8= 6+7*6
=48

the length of teacher's table=3
total length= 48+3
=51
therefore, the total length of the classroom is 51m.

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Part 1

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Part 2

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Q. (i) In a classroom, the first row of tables is set up 3m from the teacher's desk at the front of the class. All rows of tables must be 3m apart from each other. If there are 8 rows of tables and each table is 3m long, how long is the classroom?      (ii) Say that the first row of tables has 2 students. With each row, 2 more students are added. How many students can be accommodated in this arrangement?

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Q. (i) In a classroom, the first row of tables is set up 3m from the teacher's desk at the front of the class. All rows of tables must be 3m apart from each other. If there are 8 rows of tables and each table is 3m long, how long is the classroom?      (ii) Say that the first row of tables has 2 students. With each row, 2 more students are added. How many students can be accommodated in this arrangement?

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Social Distancing is an important factor of staying safe during these turbulent times. An architect must accommodate 700 people in a labor camp he’s constructing. According to the extent of social distancing, the amount of rooms in his building change. If there is always 1 m of distance between workers, he requires 43 rooms. If the distance is 2m, number of rooms are 59. If the distance is 5m, number of rooms are 107. Calculate the number of rooms if he constructs the building while practicing 10m of social distancing. 

If the architect plans to construct 10 different buildings following 1m of distancing for the first, 2m for the second and so on; calculate the total number of rooms he will construct. 

What according to you would be the most efficient building, keeping in mind social distancing and wastage of space. (value based element

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Pt.1

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Given: