# data[].attributes.body
t = 3, h = 3
Pt Nmax - vom lua  fiecare nod cu 3 chei => fiecare nod va avea 4 copii

1(rad) + 4(copiii) + 4 * 4(nepotii) + 4^3(stranepotii) = 85 noduri

1 + (t+1) + (t+1)^1 + ... + (t + 1)^h =
((t+1)^h - 1)/(t - 1) Nmax

# data[].attributes.body
1 boicu razvan

# data[].attributes.body
nivelul 1: 1*2 = 2
niv 2: 2*3*3= 18
niv 3: 18*3*3 = 162

maxim = 192