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This video covers how toSolve a quadratic equation by factoring

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Solving a quadratic equation by factoring | Algebra II | Khan Academy

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Constant 2nd difference

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f(n)=2n^2+10

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f(0)=2 f(n)=f(n-1) + 10n -14

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Constant R.O.C. of 2

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f(n)=2(2)^n

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f(0)=2 f(n)=f(n-1)x2

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Constant difference of 3

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f(n)=3n+2

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f(0)=2 f(n)=f(n-1)+3