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Sample Space: all the possible outcomes of an experiment

Event: a single result of an experiment

Experiment or Trial: an action where the result is uncertain.

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Question 1

red and yellow = 36

p.red = 1/3

p.yellow = 2/3

p.green = 1/10 = ?

1/10 = x/36+ x

36 + x = 10x

36 = 10x - x

36 = 9x

4 = x

x = 4

# data[].attributes.body
n(red and yellow) = 36

P(R) = 1/3

P(Y) = 2/3

P(G) = n(x) = 1/10

1/10 = n(x)/36 + x

36 + x = 10x

36 = 10x - x

36 = 9x

x = 4

# data[].attributes.body
Red + Yellow = 36

(P) Red = 1/3

Green = ? 1/10

9/10 = Yellow + Red

9/10 = 36

1/10 = 4

So, 4 green beads need to be added.

# data[].attributes.body
1/10=green card

9/10=red card + yellow card

9/10=36

36+x=10x

36=10x-x

36=9x

36/9=x

x=4

1/10=4

a)need to add 4 green card so the probability that green card is chosen is 1/10

# data[].attributes.body
Question 1

red=36*1/3=12

yellow=36*2/3=24

green=x

whereas

x=1/10

10x=36+x

10x-x=36

9x=36

x=36/9

x=4

# data[].attributes.body
X = 1/4 Y=1/3

X==3/12 Y=4/12

12/12 - 3/12 - 4/12 =5/12

5/12 = 25

1/12 = 5

3/12 = 15 , 4/12 = 20

A) X = 15 , Y = 20

B) 4/13 = blue

S0, 9/13 = Green + Red

9/13 = 45

1/13 =5

So,4/13 = 20

20-15 = 5

Hence, 5 blue beads needed to add.

# data[].attributes.body
(a) X = 1/4 = 3/12 , Y = 1/3 = 4/12

Probability of red

= 12/12 - 4/12 - 3/12

= 5/12

5/12 = 25

X = 15 , Y = 20

(b) X = Blue = 4/13

20 + 25 = 45 = 9/13

1/13 = 5

4/13 = 20

20 - 15 = 5

Hence, a total of 5 beads must be added.

# data[].attributes.body
X=1/4 , y=1/3

X=3/12 , Y=4/12 , 25=5/12

X=15 , Y=20

a)X=15 , Y=20

4/13=blue

9/13=20+25=45

1/13=5

4/13=20

20-15=5

b)5 blue beads must be added so that the probability of picking blue bead is 4/13.