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As we know that for both solid & hollow sphere, the capacitance is the same as the charge lie on the surface of a conduction sphere. Now for same potential the charge on both the spheres will be equal as potential V=Q/C therfore Q=CV

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Sphere A and Sphere B will have equal charges because both of them are charged to the same potential.
V= kq /r
q= Vr/k where V1=V2 and r1=r2.
From this equation we can conclude that charge depends on electric potential and radius and hence both the spheres have equal charges.

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The charges of the spheres will be equal as they have same radius and same potential.
V = kq/r

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Since both solid and hollow sphere have same radius and potential,both the spheres will have same charges.
V=kq/r
q=Vr/k

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V=kq/r
From the above equation, we can deduce that since both the spheres A and B have equal radii and potentials, their charges are equal as well. It does not depend on whether they are hollow or solid as the charges reside only on their surfaces.

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V=kq/r
q=Vr/k
Therefore from the above equation we can say that both spheres will have equal charge due to their equal potential and radius.

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Since both the spheres have the same radius and potential,the charges on both spheres will be equal.
V=kq/r

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Since both solid and hollow sphere have same radius and potential, both the spheres will have same charges from the equation,
V=kq/r

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Since both spheres have same radius and same potential both the spheres will have same charges.
V=kq/r
q=Vr/k

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since both spheres have same potential and radius, from the relation V=kq/r ,the charges on them will be equal

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V=kq/r
q=vr/k
Since both the spheres have same radius and same potential, both the spheres will  have equal charge.

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From the relation V=kq/r, we can decipher that both hollow and solid sphere will be of equal charge, as they both have equal radii and are charged to the same potential.

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The charges on both the spheres will be equal as they have the same radius and are charged to the same potential.
V=kq/r

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V=kq/r .
The charges of both the spheres will be equal as they have same radius and potential.

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The charges of both the spheres will be equal as they have the same potential and radius.
According to the equation,
V=kq/r

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Both the spheres have equal charges because they pass equal capacitance. The capacitance of a sphere depends only on its radius. It does not matter whether the sphere is hollow or solid.
Electric Potential, V = kq/r

Charge, q = Vr/k

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Since both the spheres have equal radii and potential,the charges on the two spheres will also be equal.
From equation,
V=kq/r

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As both spheres have equal potential and radius the charges of both the spheres will be equal.
V=kq/r

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The charges of both the spheres will be equal because they have same radius and potential.
V=kq/r

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The charges of both the spheres will be equal as they have equal potentials and radius.
V=kq/r
Therefore, q=(V×r)/k

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Since both the spheres have equal radius and potential , sphere A&B will have equal charges .
According to the equation ,
V=kq/r
hence q= Vr/k

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V=kq/r
q=Vr/k
both the spheres have same radius and same potential so both spheres will have equal charge.

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For the same potential,the charges will equal will be equal for the conducting spheres A and B.

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The charge on both the spheres will be equal, since the radius (Ra=Rb) and potential (Va=Vb) of the two sphere are the same.

The relation is given by,
V=kq/r

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For the same potential, the charge on both the spheres will be equal.

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The charges on both the spheres will be equal as V=kq/r

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The charges will be equal on the two spheres (qA=qB), because they are charged to same potential and have similar radii.

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THE CHARGES ARE EQUAL

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Since both the spheres are of same radius and is charged to the same potential, the charges in both the spheres will be equal.
qA=qB

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Given V1=V2
r1=r2
Charge on sphere A,q1=Vr/k    since V=kq/r
Charge on sphere B,q2=Vr/k
From above q1=q2
Therefore charge of A is equal to charge of B

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Anjali Mathew 12-C
According to the question, Va=Vb & Ra =Rb therefore since both potential and radius for sphere A and sphere B are equal from equation
V=kq/r
Interchanging to get q
q=Vr/k
Hence , the charge for both spheres will be equal.

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Here A & B have the same radius and both are charged to the same potential. Therefore charge on A=charge on B

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12C 8 Diya Cheriyakam
Both the spheres A and B will have equal charges as they have equal radius and potential
V=kq/r
Hence q=Vr/k

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V=kq/r
therefore,q=Vr/k
and both the spheres have equal potential and radius.
Hence both the spheres will have equal charge.

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the charges will be equal to each other.
i.e. qA = qB

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since it is given that both the spheres have same radius and are charged to same potential they both will have same charge according to V=kq/r
therefore, q=Vr/k

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Sphere A and Sphere B will have equal charges because both of them are charged to the same potential.
V=kq/r
q=Vr/k where V1=V2 and r1=r2.
From this equation we can conclude that charge depends on electric potential and radius and hence both the spheres have equal charges.

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Both the spheres will have the same charge as the potential and the radius of the spheres are equal.
V=kq/r

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potential, v = kq/r
hence q = vr/k.
It is given that both spheres have same radius and is charged to same potential hence both the conducting spheres will have equal charges.

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Jewel Juhana
The charge on both the spheres will be equal because they have equal radius and potential

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The charge on both the spheres will be same because their radius and potential is same. V = kq/r

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Both spheres have the same radius and potential so the charge on both will be the same.
V= kq/r

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Since the potential and radius of the spheres are equal, the charge on both the spheres will also be equal. According to the equation
V=kq/r

q=Vr/k
VA = VB and rA =rB ; hence the charges will also be equal.

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Charge on A will be equal to charge on B as both of the spheres have the same potential and the charges are equally distributed across the surface                       V=kq/r

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As it is of the same radius and the same potential, the relation between the charges will also be equal for the both the spheres.
Therefore, the relation between the charges : V = kq/r
> q = Vr/k.

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Ans: The charge on both the spheres will be the same because potential and the radius of the spheres are equal
V = kq/r
Since V and r are same, q will also be equal for both spheres.