# data[].attributes.body
Nurhidayah Fazira EQC180051

p (0,0) = 0.38
p1 (0) = 0.76
p2(0) = .55

As p (0,0) ≠ p1(0) . p2(0)

Therefore, Y1 and Y2 is not independent.

# data[].attributes.body
Y1 and Y2 are dependent since p(1,1) is not equal to p1(1)p2(1); 0.02 is not equal to 0.0384

# data[].attributes.body
0.418is not equal to 0.38

# data[].attributes.body
It is not independent

# data[].attributes.body
Not independent

# data[].attributes.body
Not independent

# data[].attributes.body
Dependent. f(y1=0)=3/15 and f(y2=0)=6/15, but f(y1=0,y2=0)=0

# data[].attributes.body
Its not independent because p(0,0) is not equal with p(1)p(2).

# data[].attributes.body
Not independent

# data[].attributes.body
Not independent

# data[].attributes.body
Not independent

# data[].attributes.body
Not independent

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Chong kah hoe
F(0,1) is not equal to Fy1 Fy2

# data[].attributes.body
p(0,0)=.38, p1(0)=0.76; p2(0)=??, hence, p(0,0)≠ p1(0) p2(0). So Y1  and Y2 are dependent

# data[].attributes.body
Not independent

# data[].attributes.body
It's not independent

# data[].attributes.body
Liu SIYU not independent

# data[].attributes.body
Not independent.

# data[].attributes.body
Dependent

# data[].attributes.body
Given F(y1,y2) not equal to F1(y1)F2(y2)

# data[].attributes.body
It's not independent

# data[].attributes.body
Dependent

# data[].attributes.body
It is dependant

# data[].attributes.body
Not independent

# data[].attributes.body
Not independent. Because is not equal

# data[].attributes.body
Not independent. Because is not equal

# data[].attributes.body
Not independent. Because is not equal

# data[].attributes.body
Not. Because is not equal

# data[].attributes.body
Not. Because is not equel

# data[].attributes.body
Not. Becaus

# data[].attributes.body
Not

# data[].attributes.body
It is independent

# data[].attributes.body
Dependent

# data[].attributes.body
Dependent  as they are not the same

Amir Raslan

# data[].attributes.body
F(y1,y2)=0.38 different
P1(0) .76
X
P2(0) .55

# data[].attributes.body
Y1 and Y2 is not independent

# data[].attributes.body
Y1 and Y2 is not independent

# data[].attributes.body
Y

# data[].attributes.body
Dependent

# data[].attributes.body
Dependent9

# data[].attributes.body
Dependent

# data[].attributes.body
Inde

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It's not
independent

# data[].attributes.body
It's not independent

# data[].attributes.body
Given

# data[].attributes.body
Dependent.

# data[].attributes.body
It is not independent

# data[].attributes.body
It is not independent because

# data[].attributes.body
It is not independent because p(0,0)

# data[].attributes.body
It is not independent because p(0,0

# data[].attributes.body
It is not independent because p

# data[].attributes.body
It is not independent because

# data[].attributes.body
It is not independent

# data[].attributes.body
It is not

# data[].attributes.body
Yes they are independent. The joint probabilty for y1=0and y2 =0 is 0.418 which is not 0.38

# data[].attributes.headline
OubeidIt is dependent because of the definition of the function 

# data[].attributes.subject
OubeidIt is dependent because of the definition of the function 

# data[].attributes.body
Nurul Fatin Szana.
Not independent because f(y1,y2) not equal to f(y1)f(y2)

# data[].attributes.body
Not independent. y1*y2 is not equal to y1y2

# data[].attributes.body
Independent

# data[].attributes.body
it is dependent

# data[].attributes.body
It's not independent

# data[].attributes.body
Not independent. As f(y1)*(y2) is not equal to f(y1y2)@0.38

# data[].attributes.body
F(y1)F (y2)=0.1216
Not independent
CHONG KAH HOE