# data[].attributes.body
50/10+2/100
b. 0.52
c. 00.52 the two zeros represent the tens and ones that show on the hundreds chart

# data[].attributes.body
180

# data[].attributes.body
I say b & c

# data[].attributes.body
a is 5 /10 + 2 /100
B is 0.52
C is 5 tens and two ones and the other is 5 tenths an 2 hundreths

# data[].attributes.body
b and c

# data[].attributes.body
The width is 12 and the area is 27

# data[].attributes.body
180

# data[].attributes.body
a. 5/10+2/100
b. 0.52
c. 5 tens 2 ones- 5 tenths 2 hundredths.

# data[].attributes.body
180!

# data[].attributes.body
a. 5/10+2/100
b. .52
c. 5tens 2ones 5 tenths 2 hundreths

# data[].attributes.body
The answers that I chose were the area is 27 and the width is 12.

# data[].attributes.body
A. 5/10 + 2/100
B. 0.52
C. 5 tens and 2 ones

# data[].attributes.body
Area=27
Width=12

# data[].attributes.body
The answers I chose were
A. 2/100+5/10
B. 0.52
C. 5 tens and 2 ones

# data[].attributes.body
15x12=180

# data[].attributes.body
a 2/100+5/10
b 0.52
c 5 tens and two ones

# data[].attributes.body
100+80 = 180

# data[].attributes.body
5/10 + 2/100
0.52
5 tenths and 2 ones

# data[].attributes.body
a.50/10+2/100
b. 0.52
c.5 tens and 2 one and the others is 5 tenth and 2 hundredth

# data[].attributes.body
180

# data[].attributes.body
180

# data[].attributes.body
A. 5/10+2/100
B. 0.52
C. 5 tenths and 2 hundredths,
5 tens and 2 ones

# data[].attributes.body
The width is 12 so the area is
15 x 12 = 180 square inches

# data[].attributes.body
A .5/10+2/100
B. 0.52
C. 5 tens 2 hundredths and 5 tens and 2 ones

# data[].attributes.body
A.  2/10 + 50/100 = 52/100
B.  0.52
C. 5 tens & 2 one

# data[].attributes.body
180

# data[].attributes.body
The width is 44
Area is 2,160

# data[].attributes.body
A.2/10+50/100 or 5/10+2/100
B.0.52
C.5 tenths and 2 hundredths
5 tens and 2 tens

# data[].attributes.body
We know that the perimeter is 54
and the length is 15 and we multiply by twelve we get 180.

# data[].attributes.body
180

# data[].attributes.body
A and B

# data[].attributes.body
180 !

# data[].attributes.body
A.  5/10+2/100=52/100
B. 0.52
C. Tens: 5  Ones: 2  Tenths: 5 Hundredths: 2

# data[].attributes.body
180!!!!

# data[].attributes.body
180

# data[].attributes.body
I think the answer is b and c

# data[].attributes.body
180

# data[].attributes.body
b and c

# data[].attributes.body
A=5/10+ 52/100
B= 0.52
C=5/10+2=52/100

# data[].attributes.body
A.5/10+2/100=52/100
B.0.52
C.0 ones 2thenths 5 hundreths

# data[].attributes.body
Area=27
Width=12
Product=27 x 12 = 180

# data[].attributes.body
B and C

# data[].attributes.body
180

# data[].attributes.body
A. 5/10+2/100=52/100
B.0.52
C.2 ones, 5 tens, and 0 hundreds

# data[].attributes.body
180

# data[].attributes.body
180

# data[].attributes.body
2/100+5/10
0.52
5 tenths and 2 hundredths

# data[].attributes.body
Width=12
Area=180

# data[].attributes.body
A. 2/10 + 32/100 = 52/100
B. 0.52
C. 5 tens + 2 ones

# data[].attributes.body
Width = 12
Area = 180

# data[].attributes.body
180

# data[].attributes.body
B&C

# data[].attributes.body
a.2/10 +32/100=52/100
b.0.52
c.5 tens +2 ones

# data[].attributes.body
180 😁

# data[].attributes.body
B&C