# data[].attributes.body
Hello

# data[].attributes.body
ICT is my post!

# data[].attributes.body
Jude

# data[].attributes.body
Hello

# data[].attributes.body
Interesting!

# data[].attributes.body
x = 12

# data[].attributes.body
(y+2)

7

# data[].attributes.body
(y/5) - (y+2)/7 = 2

(y/5) - (y+2)/7 x 5 = 2 x 5

y - (y+2)/35 = 10

y - (y+2)/35 x 35 = 10 x 35

y + t

# data[].attributes.body
(y/5) - (y+2)/7 = 2

# data[].attributes.body
7(y/5-y+2/7)=2x7

7y/5-7y+2/7=14

# data[].attributes.body
x = 12

# data[].attributes.body
x = 12

# data[].attributes.body
9-（-7）=16

X=12

# data[].attributes.body
9-(4x/3)=-7

9-16=-7

PROCESSING...............

X=12

# data[].attributes.body
9 -(4x/3) = -7

multiply by 3 on both sides

3[ 9 - (4x/3 ] = -21

27 -

# data[].attributes.body
9 - (4x/3) = -7

9 - (4x/3) x 3 = -7 x 3

27 - 4x = -21

27 + 21 - 4x = -21 +21

48 - 4x = 0

48 - 4x + 4x = 0 + 4x

48 = 4x

12 = x

# data[].attributes.body
G'Day Mr Yong

Good Afternoon :)

# data[].attributes.body
(y/5)-(y+2)/7=2

# data[].attributes.body
x=

# data[].attributes.body
Answer to question:

9-(4x/3)= -7

(9-4x/3)x3= -7x3

9-4x=-21x

x=12

G'day

# data[].attributes.body
x = 10

# data[].attributes.body
x=10

# data[].attributes.body
Solve

12 +(2x/5) = 16

# data[].attributes.body
Multiply both sides by the denominator

# data[].attributes.body
x=10

# data[].attributes.body
x + (x/4) = 15

# data[].attributes.body
x =

# data[].attributes.body
Solve

1.) 5x + 3 = 4(x+ 7)

2.) 5x + 3 = 4x + 28

3.) 5x +3 -3 = 4x +28 - 3

4.) 5x = 4x +25

5.) 5x- 4x = 4x -25 -4x

6.) x = 25 (ANSWER!)

# data[].attributes.body
Solve 2x + 1 = 3

# data[].attributes.body
welcome to e-learning 2014