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@Kamrie Why did you get 107?

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I am so confused and lost and I have no idea what y'all are talking about

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the b and c part would be:

211,311,411,511,611,711,811, and 911.

a total of 8.

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Once you have your total( 8 million)

then start over with each bullet and find the

number of restricted numbers

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I found this answer to be 7,919,900. I found this by subtracting 8,000,000 by 80,000 and then subtracting the reserved for fictional uses numbers.

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Darby is right. Emergency numbers are just examples

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Oh im starting to get it.

kinda but not  really

So I get 8 mil, then multiplied 10x10x10x10 for the 4 X's. Then I multiply that by 8 since that is the possible numbers for A? and subtract from 8 mil?

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I got 7919900...

first multiply 8x10x10x10x10x10x10

then the restrictions is 8x10x10x10x10

cause like 'B' and 'C' can't both equal 1 so that takes away 8 combinations so you have to multiply the 8 and 10000

10000= the four last digits that vary from 0-9

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there are three basic steps.

The first is to find total without restrictions

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JD                                           Garza

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JD                                           Garza

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7,919,900 with restrictions

multiply 8x10x10x10x10x10x10

then subtract 8x10x10x10x10

then subtract 100

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I got 8 million without restrictions by multiplying 8 times 10^6

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I also got 8 million

Why is it only 100?  help

I am about to cry help

WHY 80,000

why 8 times 10000

no one will answer ahhh

okay so you subtract 80,000 then why

100

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how are you getting 80000 combos????????? yes veronica

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after you subtract 80 thousand from 8 million just subtract another 100 for the fictional numbers

A (8) times the four x's (10x10x10x10) equals 80 thousand