# data[].attributes.body
1) 17 ppm of pollutants can be extracted from kerosene when is is passed through 3 ft of clay.

3) Solve f(x)=2
x={-20, 20}
Determine zeros of g: (0, -2.3), (0, 2.3)

# data[].attributes.body
After the pollutants are passed thru 3ft of clay inside of pipes, there would be 17 ppm of pollutants removed.

# data[].attributes.body
2) Solve h(0) x=1
h(x)=-4 x=3
Solve h(h(h(0)))x=-4

# data[].attributes.body
5) G (-2) = -13.25

# data[].attributes.body
3) x={20, -20}
Zeros of g={0,-7/3}
4) t=9

# data[].attributes.body
According to the function p(3)=17, when kersosene passes through 3 feet of clay pipe 17ppm of kerosene is removed.

# data[].attributes.body
2.) If h={(-4,7), (0,-4),(1,0),(3,-4),(7,-5)} , evaluate h(0). Find the zeros of h. solve h(x)=-4. Find h(h(h(0))).
h(0)= 1
h(x)=-4

# data[].attributes.body
1.) For every 3 ft of clay kerosene is passed through, there are 17 pollutants pulled out.

# data[].attributes.body
3. Given f(x)=5x², the value for which f(x)=2 is .632.

The zeros of G are 0 and -2.33

# data[].attributes.body
1) 17ppm of pollutants get extracted when the keroscene passes through 3 ft of clay.
2)  h(0)=1
h(x)=-4   x={0,3}
h(h(h(0)))=-4

# data[].attributes.body
2) If h={(-4,7),(0,-4),(1,0), (3,-4), (7,-5)}, evaluate h(0). Find the zeros of h. Solve h(x)=-4. Find h(h(h(0))).

solve h(0) x=1
h(x)=-4 x=3
solve h(h(h(0))) x=-4

4) Given f(t)=2√t+5 and g(t)=t+2, determine the values of t for which f(t)=g(t).

Solve f(t)=g(t) t={(4,6)}

5) Given that g is a linear function such that g(1)=7 and g(5)=-12, evaluate g(-2).

Solve g(-2) x=

# data[].attributes.body
The values of x for which f(x)=2 is .625

The zeros of G are approximately
X= -7/3 and X = 0

# data[].attributes.body
4).  The Values of x for which f(x) = g(x) are 4 and 6.
Not sure if that is right though..

# data[].attributes.body
Problem 5)
Given that G is a linear function such that g(1) = 7 and g(5)=-12 evaluate g(-2).

Solve g(-2)=       20  Because it is a linear function.
(Idk)
-Peter

# data[].attributes.body
1) Evaluate h(0)
H(0)=4
2) Find zeros of h
Solve for h(x)=0
x=1
3) Solve h(x)=-4
x=3, x=0
4) Find h(h(h(0)))
= h(h(-4))
= H()7 = -5