# data[].attributes.body
When the divider is shifted to the left, the exposed-surface area of the water is smaller and the rate of evaporation is slower, so less water can evaporate from section A and less water vapour will be formed. Less water vapour touch the cooler inner surface of the thin metal sheet and less warer droplets is formed. Less water droplets slide down to B.

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She can make the thin sheet of metal colder by putting ice on top.

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Make the thin metal sheet cooler.

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He can place some ice cubes on the thin metal sheet

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Animal w gets protection when hiding in plant p

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Amy can put ice on the metal sheet on top of B.

# data[].attributes.body
Less exposed surface area of water in A is exposed so less water evaporates due to the heat of the light and becomes less warm water vapour which comes into contact with the cooler inner surface of the metal sheet, lost heat and condensed into less water droplets which dripped in b so less water is present.

# data[].attributes.body
When the strong spotlight is on the surrounding will gain heat then it will be warmer then the water in section A then the air will touch the water and the water will gain heat and evaporate then it will rise up to the cover then will condense into water droplets the will drip down the cover and when more water droplets come it will become heavier and drop down into B

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Place ice on top of the metal sheet

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Make the temperature in the room colder

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Move the thin sheet of metal Lower

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Decrease as there is less water vapour to condensate into water droplets

# data[].attributes.body
Make the thin sheet of metal colder , like placing ice on top of it

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The water will decrease because the surface area decreased,so the rate of evaporation decreased,forming less water droplets.

# data[].attributes.body
The amount of water found in section B will increase. This is because there is a smaller surface area, hence, the water in section A will evaporate faster, so within 3 hours, there should be more water in section B then the setup in question (a)

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The rate of condensation will decrease as there will be less water Vapor condensing

# data[].attributes.body
The amount of water 💧 in section B will decrease. This is because the exposed surface area of water 💧 in section A became smaller when the divider was pushed towards it and so, less water 💧 from section A will gain heat from the spotlight and form less water 💦 vapour and less water 💦 vapour will lose heat and condense to form less water 💦 droplets that will be collected in section B.

# data[].attributes.body
The water in section B will decrease. This is because there is a lesser exposed surface area, so the water in section A will evaporate, but in a slower rate.

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He can add ice cubes to the top of the thin metal sheet.

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The water collected in section B will be the same as all the water will soon evaporate and condense into water droplet and drip down to section B

# data[].attributes.body
The amount of water in sevtion b would increase . When the divider is moved to the left , section b would be bigger , habing more exposed surface area on the thin metal sheet which water condenses on , allowing more water vapour to condense

# data[].attributes.body
The water in B will decrease. As the surface area exposed is smaller, less water from section A will evaporate and less water vapour will condense into less water droplets. Hence, collecting less water in section B.

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Decrease. There is less exposed surface so there is less water vapour condense into water droplets. - Ella

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It will decrease, as there will be lesser exposed surface area and lesser water will gain heat and evaporate.

# data[].attributes.body
Water in section A gained heat from the strong spotlight and evaporated.The water vapour then touched the cooler inner surface of the metal sheet, lost heat and condensed into water droplets.The heavy droplets would then tilt towards section b and drip onto the ground,thus,there would be water in section b after some time.

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It would remain the same because the same amount of water was still being evaporated, meaning that there would the same amount of water droplets condensed

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It will decrease, there will be less water vapour to condense into water droplets

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Add ice cubes on top of the thin sheet of metal

# data[].attributes.body
Decrease. The Exposed surface area became smaller , hence , lesser evaporation rate and lesser water ending up in section B

# data[].attributes.body
Less. The water has a smaller exposed surface area so less warm water vapour will be evaporated from water.

# data[].attributes.body
The amount of water in section B would increase as the amount of exposed surface area is increases

# data[].attributes.body
The water in section A gains heat from the strong spotlight, evaporates into water vapour, touches the cooler surface of the thin metal sheet and loses heat, condensing into water droplets. The water droplets then rolls down the thin metal sheet as the metal sheet is slanted, and drips down into section B’s side, therefore there was water in section B.

# data[].attributes.body
Make the exposed surface area of the water in section A bigger

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The strong spotlight produces heat. The water in section A gained heat from the heat produced by the spotlight and evaporated into water vapour. The warm water vapour then touched the cooler surface of the inner surface of the thin sheet of metal, lost heat and condensed to form water droplets. The water droplets then slide down the thin sheet of metal and dripped into section B.

# data[].attributes.body
The spotlight is a heat source. Water in A gains heat from it and evaporated into water vapour. The warm water vapour came into contact with the cooler thin metal sheet, lost heat and condensed into water droplets which dripped into B.

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As the strong spotlight gives of heat , the water in section at evaporats . Then the water vapour touches the thin sheet of metal and conden into wa droplets. Then the water droplets will slide down to section B , hence water apearig In section B

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The heat from the spotlight evaporated the water. The warm water vapour came in contact with the cooler inner surface, lost heat and condensed into water droplets which dropped into section B since the metal sheet is slanted.

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He can put ice cubes on top of the thin sheet of metal.

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There will be lesser water in section B, because the water in section A has a smaller exposed area which decreases the rate of evaporation and there will be lesser water vapour in the air to condense into water droplets in section B

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When the spotlight is on, heat is produced. The water in section a gain heat and evaporated in to water vapour. The water vapour touched to cooler inner surface of the metal lid, lose heat and condense into water droplets. The water droplets will slide towards the plastic container due to the slant and the gravity. Water droplets collected there will become heavier and heavier and finally drips down into the plastic container -Ella

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When the torch was turned on, there will be heat produced by it. The water gained heat from the torch and evaporated to become water vapour. The thin sheet of metal is cold as it is in a cold room. The water vapour then touches the cooler surface of the thin sheet of metal and condenses into water droplets. Lastly, it would slide down as the thin sheet of metal was slanted and would fall into section b.

# data[].attributes.body
Water in a gains heat to the surrounding and evaporates into water Vapor which loses heat and turns into water droplets.

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It will decrease, as there is a smaller exposed surface area so the rate of evaporation would be less, and there would be less condensed water vapour into water droplets.

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It will decrease because there is less expose surface in a so less rate of evaporation so b will collect less water

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Decrease due to decrease in exposed surface area so less water can evaporate

# data[].attributes.body
The amount of water in section B will decrease. It is because the exposed surface area of water in section A became smaller, so less water from section A will gain heat from the surroundings and form less water vapour and less water vapour will lose heat and condense to form less water droplets which less water droplets will be collected in section B.

# data[].attributes.body
Water from A gained heat from its surroundings and evaporated into water vapour. The warm water vapour came in contact with the cooler, inner surface of the metal lid, lost heat and condensed into water droplets. The water droplets will flow down to B. There, gravity will pull them down.

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Decrease.The water has less exposed surface area with air.Water will evaporate slower and condense into water droplets slower.

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The water gains heat from the spotlight and evaporates into water vapour and touches the cooler surface of the metal sheet and condenses into water droplets. The water droplets will drip down into section a and b.

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When amy switched on the strong spotlight for 3 hours, the water in section A will gain heat from the spotlight and evaporate. The water vapour then loses heat to the divider and condenses into water droplets, explaining why there was water in section B.

# data[].attributes.body
Th strong spotlight increased the rate of evaporation,so the water in section A gained heat and evaporated into water vapour.The water vapour touched the cooler surface of the slanted metal sheet,condensed into water droplets which then dripped down into section B.

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When the water in section A evaporates, the water vapour condenses on the thin sheet of metal and falls into section B

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The water evaporated and condensed into water

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Water gained heat and evaporated into water vapour which touched the cooler inner surface of the metal sheet lost heat and condensed into water droplets

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The strong spotlight gives out heat. Water in sections A gains heat and evaporates. The warm water pair will touch the cooler, inner surface of the thin metal sheet and will lose heat and condense into water droplets. The water droplets will slide down the thin metal sheet and drip down into section B.

# data[].attributes.body
Water in section A will gain heat to the strong spot light and evaporate, the water vapour will touch the cooler surface on the thin sheet of metal causing it to lose heat and condense into water droplets

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The water 💦 in section A gained heat from the strong spotlight and evaporated into water vapour that came into contact with the cooler inner surface of the thin metal. The water vapour then lost heat and condensed into water 💧 droplets which slid down the thin metal and as more water droplets condensed on the metal, the heavier the water 💧 droplets became and dripped into section B. Making water 🚿 collect in section B.

# data[].attributes.body
The water from section A gained heat from the strong spotlight and evaporated into watervapour which flowed down the ceiling of the box and entered section B

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The strong flashlight emitted some heat, heating the water and making it evaporate into water vapour, when it evaporates, it touches the cooler surface of the metal and condenses into water droplets before sliding towards the other end as the metal is slanted before dropping off the metal sheet

# data[].attributes.body
Water from section A gained heat from the spotlight evaporated into water vapour touch the metal sheet lost heat and condensed into water droplets

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The water in Section A gained heat from the strong spotlight and evaporated to form water vapour. The warm water vapour touched the cooler, inner surface of the thin sheet of metal, lost heat and condensed to form water droplets which fell into section B.

# data[].attributes.body
The Water in section A gained heat from the air that has gained heat from the torch, the water gained heat and evaporated in warm water vapour. The warm water vapour touched the cooler thin metal sheet and Lost heat and condens into samll water droplets which rolled Down resulting in water at section b

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The strong spotlight heated the water in A , the water gained heat and evaporated , turning into water vapour . The warmer water vapour thrn loses heat to the cooler thin sheet of metal above section b , condensing into tiny water droplets that drops down into section b

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Water in section A gained heat from the spotlight,and evaporated into warm water vapour.It touched the cooler,thin metal sheet,lost heat to it and condensed into water droplets.The water droplets flowed down along the sheet and dropped down to B.

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When the water evaporated into water vapour,warm water vapour inside section A escaped through the tint gap in between, it came in contact with the cooler inner surface of section B, lost heat and condensed into water droplets. The water then gets heavy and drops down on the ground because of gravity.

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Water from section a evaporated and condensed on the sealing and slider to section b before dropping

# data[].attributes.body
The water in section A gained heat from the strong spotlight and evaporated into warm water vapour. The warm water vapour touched the cooler, inner surface of the metal sheet and lost heat and condensed into tiny water droplets. Which dripped down to section B.

# data[].attributes.body
The water in section A gained heat from the strong flashlight and evaporated into water vapour. The water vapour then lost heat on to the cooler thin sheet metal, and condensed into water droplets, which dripped down to section B and fell down as water droplets onto section B.

# data[].attributes.body
The light from the strong flashlight evaporated the water in section A into warm water vapour, the warm water vapour then touched the cooler surface and condensed into water droplets the water droplets then slid down the slanted covering of the setup and dripped into section B

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Water from section A gained heat from the surrounding air, evaporated to form water vapour. The warm water vapour touched the cooler, inner surface of the thin sheet of metal, lost heat to the container and condensed to form water droplets on the inner side of the container. The water droplets will slide down to section B, when the water droplets gather together and is heavy enough, it will drop down in section B as it got pulled down by gravity.

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The plant P can be a resting place for animal W.

-Ella

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When the animal hide inside the plant p, the scent of p attracts insects for animal w to eat

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Animal W can hide from it‘s predators while still passing out it’s droppings in the day. Another way that Animal W can benefit by staying in plant P is when Animal W’s predators try to eat it while animal w is inside of plant P, the predators will get trapped and absorbed by plant P, providing protection for Animal W

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When Animal W hides inside Plant P, Plant P provides protection for Animal W. This makes it more difficult for Animal W’s predators to spot Animal W, increasing Animal W’s survival.

Plant P also carries out photosynthesis, producing oxygen. The oxygen produced is used by Animal W for respiration, thus allowing it to survive.

Plant P also gives shelter for Animal W.

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The structure of Plant P makes it hard for the predators of W to eat W as when they go inside the plant, they might slip on the walls of the plant and fall down on the digestive juices. So the predators will stay away from Plant P and animal W.

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Animal w can hide inside the pitcher shaped like plant so predators will not spot it easily and eat it

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Animal W can feed on the insects trapped in plant P’s structures and thus get more food.

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Animal W can hide in plant P for protection from predators,this increases the chances of survival for animal W

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The animal gets protection. If the predator wants to enter plant P , they will get killed as the digestive juices of the plant can digest the predator

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Animal W can hide from its predators it the pitcher structure so that it will not be eaten.

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Animal W cannot be easily spotted by its predators when hiding inside plant P. It will also be able to get more food by hiding from its prey. -Swathi

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By hiding inside Plant P, Animal W can get its protection and will have a lesser chance of getting eaten by predators

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When animal w rests in plant p, there are dead insects trapped inside. Animal w can eat the dead insects inside giving it food and nutrients and shelter for animal w from its predator.So this will have a benefit to animal w.

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Animal W is unaffected by plant Ps digestive juices so W can hide from its predator and also rest without worry of predators

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Animal W can take shelter in the structure of plant P and hide from predators while also resting.This improves the chances of survival for animal W.

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When animal w is in plant p, plant p could attract small animals and animal w will eat the small animals

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Being in Plant P allows Animal W to hide from predators and not be easily spotted

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Animal W can stop and rest in plant P, regaining its strength and saving energy, having a lower chance of dying due to tiredness.

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staying inside Plant P, Animal W can hide from predators

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The structure makes it hard for predatOrs Of W have a hard time eating w aas they might slip in and fall into p and get eaten, hence the structure of p gives w a safe space to stay

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plant p has nectar which attracts insects that animal w can eat.

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Predators will not be able to eat it as it is more protected.

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Animal w can benefit by getting protection hiding inside the plant from the predator.