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Solution: y = -1/2x - 1
Explanation: The problem itself provides you with the y-intercept and the x-intercept. First I started with plotting the y and x-intercepts and from there I figured out a "rule" or the slope. Since the y-intercept is -1 and the x-intercept is 2, the only way to get these two numbers is to go up by 1 and over 2.

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Equation: y=2x+4
Explination: The problem already gives you the y-intercept and the point (-1,2). First you graph (-1,2) then go up two and over one.

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equation~ y=3x
Explanation~ the point (-2,3) yo would plot that on the graph and go up 3 over 1 because the slope is 3

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Solution: x=2
Explanation: I was giving the point (2,4) and it has to be an undefined slope. Since there is no y coordinate and only x, and y coordinate point meets it. this works because it goes straight up ( undefined) because any y coordinate works the 4 does work.

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Solution: y=-4x+ 6
Explanation: First I plotted the points it had given me (1, 3) (-1, 2), then to find the slope of the line I counted the rise and the run between the two points and it came out to be -4, and I knew that if I kept going with this that the y-intercept would be 6.

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Solution: y=3x + 9
Explanation: First I plotted the point (-2, 3) and I knew that the slope was 3 (or 3 over 1) so the rise was 3 and the run was 1. So from (-2,3) I went up 3 on the y axis and to the right on the x axis by one.

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Solution: y=\frac{1}{2}x+2.5
Explanation: First I set my Y intercept to 2.5. I then set my slope to 1/2. This means that it would go down 1, and left 2 and up one, and right 2. Because of this it was able to intercept both points.

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Solution:  X=4
Explanation: It tells us the line is parallel to X=5. This means it has to have the same slope. It also has to pass thru the point of (4,-2). The only way it can pass thru (4,-2) and have the same slope is to be a vertical line where x=4.

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Answer:  y=-3x+3
Explanation: I put the numbers in slope-intercept form. I graphed the y intercept at (0,3). I used the equation of the line to solve for y when x=1. This gave me another data point of (1,0) to graph.

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Solution: y=-3x+3
Explanation: I started by graphing the y intercept and then putting in the slope. Once I got enough points I figured out my answer or y=-3x+3

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Solution: y=1x+2
Explanation: I first graphed the line that is given. I then plotted my points and tried to figure out how I could make them parallel to each other. I figured out that it is an undefined slope. I then used that and figured out that my point has to be used by the x intercept instead of the y intercept.

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y=1/2x - 1
First I plotted the x intercept of 2 and y intercept of -1 then when counting for slope I got 1 up and 2 to the right which comes to a slope of 1/2.

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y=3x+9
first I plotted the first point of (-2,3) then plotted the slope of 3 which later made a y-intercept of 9.

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Equation~ 2x-1
Explanation~the x intercept is 2 and the y intercept is -1 so you would go up by 2 and over 1 to the right.

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Equation:   y-2=0(x-3)
Explanation: you are provided with the slope of 0 and contains the point (-3,2) giving that the slope is zero means that any point with the y being 2 would work in this problem

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Equation:    x=2
Explanation: you are given the point (2,4) and the information that the slope is undefined so all you need to do is plot any point on the x intercept of 2 and it will be an undefined slope.

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Solution: Y=1/2x+2.5 Explanation: First, I plotted the coordinates (1,3) and (-1,2). Nest, I found the slope of the two points to be 1/2 and after drawing the line the Y intercept was 2.5.

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Solution: y=-3x+3
Explanation: So what you needed to do for this problem was to create slope equation. I used the form y=mx+b so what I did was take the slope of -3 and the y intercept of 3 so the m is slope and so it would be y=-3x+b and then plugged in the b which is y intercept and so it would be y=-3x+3.

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Equation: y=-3x+3
Explanation: This problem already has everything you need for slope incerpt form so just do that form of slope equation.
first take y=mx+b and take the slope of -3 and the y-intercept of 3, since m= the slope, and b=y-intercept. I just filled it in. so y=-3x+3
To graph this, I set my point at the y-intercept (0,3) , then go down 3 and right 1 becuase it is a negative slope.

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Solution: Y=3x+9 Explanation: First I plotted the coordinates (-2,3), then I did the slope of 3 from that point up 3 over 1 and then estimated the Y intercept to be 9

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Equation : y=1/2 + -1
Explantation: The problem gave you the x-intercept and the y-intercept. So to start I plotted those points (0,-1) and (2,0) then I counted the slope between those two points. Which is up 1 over 2 or positive 1/2. Now that we have both the slope (1/2) and the y-intercept ((0,-1))  them fill them in to y=mx+b or slope intercept form. Another way you could have done this was to use m=\frac{y_2-y_1}{x_2-x_1}
and fill in the x-intercept (2,0) and the y-intercept (0,-1)

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Solution: y-5=-2/3(x+2)
Explanation:
First I graphed the point, (-4,5) and used the slope, -2/3 to rise 2 and run 3, getting me to my next point, (-1,3). I then used point slope form, getting me y-5=-2/3(x+4)

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Solution: y=2x
Problem: create a parallel line to
2x-y=-2 that passes through the point (0,0)
Explanation: by adding the opposite and subtracting 2x from both sides and dividing everything by -1 you get the equation y=-2x+2. since the line has to be parallel to that, I take the slope and use the y intercept 0.
Graph:

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Solution: y-3=3(x+2)
Explanation:
First I plotted the point (-2,3) and used the slope, 3, to rise three and run 1, getting me to my next point, (-1,6). Then I used my point and my slope and put it into point slope form, giving me y-3=3(x+2)

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Solution: y-3=3(x+2)
Explanation: I first graphed the point (-2, 3) and then I added the slope and that was 3 so I went up 3 and over 1. My next point on the graph was (-1, 6). So that's how I got my solution which is y-3=3(x+2).

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Solution: Y= 1/2 x+2.5
Problem: Graph and create an equation for the line that points (1,3) and (-1,2) make
Explanation: by subtracting 2 from 3 (which is 1) and putting it over
1-(-1) you get a slope of 1/2 and when graphed you see the y-intercept of 2.5.
Graph:

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Solution: y=-⅔(x+4) +5
How I got this:
How I got this was that I graphed the points (-4,5), then saw that my slope was -2/3 so I went down -2 and sideways 3 so the fraction of that is -2/3 which is the rise over run but still the slope that was given to me. How I got my equation was that I knew that the slope was -2/3 so that´s to the left of my parenthesis and the x and x value (-4) is in the parenthesis, and to the left of the parenthesis is the y value that we are adding (also 5)

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Equation: y = -3x +3
Explanation: First I plotted my point and I knew that the y intercept was 3 so the point would have to be (0,3). The slope was -3 so i kept moving down the graph and adding points like (1,0), (2,-3) and (7,-1). My y intercept was 3 and my slope was -3 so the equation would be y=-3x +3.

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Equation: y=3x+9
Explanation: First I plotted my point (-2,3) on my graph. After I plotted my point, I saw my slope was 3 so I used my slope to keep adding points like (-3,0) (-1,6) and (0,9). My y intercept was 9 so I could create my equation y =3x+9 because the y intercept is 9 and the slope was 3.

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Soultion= y=3(x+2)

How I got this:
How I got this was that I graphed the points (-2,3), then saw that my slope was 3 so I went up 3 and sideways one so the fraction of that is 3/1 which is the rise over run but still the slope that was given to me. How I got my equation was that I knew that the slope was 3 so that´s to the left of my parenthesis and the x and x value (2) is in the parenthesis, and to the left of the parenthesis is the y value that we are adding (also 3)