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10x2-12

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3rd Question:-
L6

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[11:37] Anusha Raikar

a. 10Y+7                                                   b.n/2-1                                                     c.3r+2

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General rule -
- No. of f = 4t
15th pattern -
- Rule = 4n
=4 x 15
= 60 matchsticks for the 15th pattern

Q2 -
Rule - No. of matchsticks = Shape no. x 3 + 2
6 - 20
7 - 23
8 - 26
9 - 29
10 - 32
50 - 152

Q5 -
Rule - 10 x 2 - 12
= 8

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1.
N = No. of F
4n
60 Matchsticks required
2.
A = No. of Arrows
3 x a + 2
6= 20
7= 23
8= 26
9= 29
10= 32
50= 152
3.
6l
is the perimeter of the hexagon
4.
a. 10y + 7
b. n/2 - 1
c. Raju's Age = R
Raju's Father Age = F
3r x 2 = f
5.
[10+12] x 2
=22 x 2
=44
The First Floor Has 44 Rooms

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rule 4n

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The Rule is
=4n
And no of F are
=15 so then 15x4=60

Q2- pattern                         Q2-The Rule is  3x+2

20
23
26
29
32
152

Q5-

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Q1.Rule is 4n
So 4x15 will be 60
Answer is 60 matchstick/stick
Q2. Rule is 3Y+2 So,
6=20
7=23
8=26
9=29
10=32
50=152

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Q1
4n
n=15
4*15
= 60
Q2
6 - 20
7 - 23
8 - 26
9 - 29
10 - 32
50 - 152
rule - 2+3n
Q3
Hexagon p = 6l
Q4
a. 10y + 7
b. n/2 - 1
c. 3r + 2
Q5
2*10 - 12
= 8
Q6
a. 3b - 4
b. 60/5 = 12
c. a-2
Q7
2n
n = 12
2 * 12
= 24

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rule -4n
60 match sticks are required for 15th F

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1st- Rule- 4n
15th- 60

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Q1. Welcome
Q2. All

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Question-1
Answer- 4n
= 4×15
= 60
60 tooth picks will be needed in the 15th pattern

Question 2 -
Ans
Shape number × 3 +2
6 - 20
7 - 23
8 - 26
9 -29
10 -32
50 - 152

Question 3
Ans
Perimeter = l× 6

Question 4 -
Ans a
Y×10+7
Ans b
N÷2-1
Ans c
3× raju age +2

Question 5-
Ans
1st floor has = 10 +12×2
= 44 rooms

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a} 10y+ 7
b} (n divided by 2)-1
c} 3r+ 2

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Q1
Rule- 4n
N=no of Fs
N=15
15x4= 60
60 matchsticks

Q2
Rule -3p+2
P= no of triangles
6= 20
7=23
8= 26
9= 29
10=32
50=152

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Q.1) The answer will be 4n
This is because everytime it is increasing by 4

15th will be-
=15x4
= 60

Therefore, using the rule 4n 15th will be 60 matchsticks

Q.2) The rule will be 3n+2
This is because each time it is increasing by three and the first one is 5 (2 more than 3)

6-20
7-23
8-26
9-29
10-32
50-152

Q.3)
The rule will be 6l
This is because hexagon has equal sides and 6 sides

Q.4)
a. 10y+7
b. 2/n-1
c. 3r+2

Q.5)
=(10+12)÷2
=22÷2
=11

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Q1
General Rule :

No.of matchstick= 4n

15th pattern:

Rule = 4n

=4 × 15

=60

Final- 60 matchsticks will be needed for the 15th pattern.

Q2
Rule
Number of matchsticks=
Shape Number × 3 + 2
Shape Number= s
3s+2

6-20
7-23
8-26
9-29
10-32
50-152

Q3
Perimeter= 6L

Q4
a) 10y + 7
b) ( n ÷ 2 ) - 1
c) Raju Age= r
Raju Father= 3r + 2

Q5
1st floor = f
Equation: 2f-12=10
Solution: f=11
Final- 1st floor has 11 rooms if ground floor has 10 rooms

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Q 1
Ans- n = no. of f's
4n=
4X15 =
60 no. of matchsticks will be requried

Q2 =
Ans=
6-20
7-23
8-26
9-29
10-32
50-152
Fomula= 3n+2
explanation= we must multiply 3 by number of arows and then add 2 to the product

4.

a. 10y+7

b. 2/n-1

c. 3r+2

5.
10 rooms on the ground floor
10x2=20
20+12=
32 rooms
there are total 32 rooms on the ground floor

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Q1 .1 = 4n
2 = 8n
1 multiplied by 4
15 multiplied by 4 = 60
final answer = 60
Q2. formula =3x +2
5=17 ,
6=17+3=20 ,
7=23
8=26
9=29
10=32
50=152
Q4.
A.10y+7
B.n/2-1
C.3r+2

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CWUPF Chinglen waikhom universal padlet former 

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CWUPF Chinglen waikhom universal padlet former 

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Q1
The pattern is, that it increases by 4 every time. the algebraic formula it is 4xn so 15th will be 60 yes
Q2
Rule is - 3 x n + 2

50 of those will be.. 152 toothpicks.
10 of those will be.. 32 toothpicks.... " wow "
9 of those will be... 29 tootpicks...
8 of those will be... 26 toothpicks

Q3
10xy + 7
2(i dont have divide in my pc) n - 1
3xr + 2
Q4
20 - 12 = 8

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One F is =4n
For 15 F we will need 60 toothpicks

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1= 4
2=8
rule=4n
for 15 = 15x4
60

qestion 2-
rule= 3x+2
6- 20
723
8-26
9-29
10-32
50- 152

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Rule- No. of Shape x 3 + 2
6- 20
7- 23
8- 26
9- 29
10- 32
50- 152

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Ans 3 -l ×6