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Then what about

g(x)=(b+1+1)x and I set b=-1 ?

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g(x) = b + 1x?

Do you mean g(x) = (b + 1)x?

They are not the same.

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Help! Why the function in 1b did not fit with 1a?

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You never set the b to 4. Also your a seems like never set to 1

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No the graphs cannot fit together.

Why?

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- Instructions to the students:

Activity 1a (Set in BLUE)

Construct the graph, f(x) = ax with the virtual manipulative at this site (http://nlvm.usu.edu/en/nav/frames_asid_109_g_4_t_2.html) and set a as 2

Note: a, b and c are variables that you can use for the later activities.

Activity 1b: (Set in Red)

Are you able to construct the same graph in Activity 1a with function g(x). variable, b and other operators?

Hints:  Construct the graph, g(x) = (b/2)x, set b as 4.

Paste your equations on the board and discuss your observation

(Do the graphs fit together and why?). Image is allowed.

Activity 1c: (Set in Green)

Construct the graph, h(x) = ax + c. Set c as 0. What do you notice?

Increase c gradually. What do you notice?

Compare f(x) = ax and h(x) = ax +c.

What has changed? How has it changed?

What has remained unchanged?